Files
TypeScript/tests/cases/fourslash
Andy 735a46f838 If parsing a function type fails, parseTypeReference() to ensure something is returned (#24567)
* If parsing a function type fails, parseTypeReference() to ensure something is returned

* Avoid tryParse

* Add missing semicolon

* Don't check for undefined, check for missing type

* Don't set parameters undefined, set to missingList and return false

* Update API baselines

* Code review
2018-06-05 10:24:37 -07:00
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2018-04-16 15:59:22 -07:00
2018-05-04 11:29:54 -07:00