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Remove unnecessary check. Classes always have exports.

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This commit is contained in:
Cyrus Najmabadi
2015-04-19 23:23:44 -07:00
parent e9a73e0cf8
commit ee6c7dc0e4
1 changed files with 13 additions and 14 deletions
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27
src/compiler/binder.ts
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@@ -601,22 +601,21 @@ module ts {
}
let symbol = node.symbol;
if (symbol.exports) {
// TypeScript 1.0 spec (April 2014): 8.4
// Every class automatically contains a static property member named 'prototype',
// the type of which is an instantiation of the class type with type Any supplied as a type argument for each type parameter.
// It is an error to explicitly declare a static property member with the name 'prototype'.
let prototypeSymbol = createSymbol(SymbolFlags.Property | SymbolFlags.Prototype, "prototype");
if (hasProperty(symbol.exports, prototypeSymbol.name)) {
if (node.name) {
node.name.parent = node;
}
file.bindDiagnostics.push(createDiagnosticForNode(symbol.exports[prototypeSymbol.name].declarations[0],
Diagnostics.Duplicate_identifier_0, prototypeSymbol.name));
// TypeScript 1.0 spec (April 2014): 8.4
// Every class automatically contains a static property member named 'prototype',
// the type of which is an instantiation of the class type with type Any supplied as a type argument for each type parameter.
// It is an error to explicitly declare a static property member with the name 'prototype'.
let prototypeSymbol = createSymbol(SymbolFlags.Property | SymbolFlags.Prototype, "prototype");
if (hasProperty(symbol.exports, prototypeSymbol.name)) {
if (node.name) {
node.name.parent = node;
}
symbol.exports[prototypeSymbol.name] = prototypeSymbol;
prototypeSymbol.parent = symbol;
file.bindDiagnostics.push(createDiagnosticForNode(symbol.exports[prototypeSymbol.name].declarations[0],
Diagnostics.Duplicate_identifier_0, prototypeSymbol.name));
}
symbol.exports[prototypeSymbol.name] = prototypeSymbol;
prototypeSymbol.parent = symbol;
return SymbolFlags.Class;
}