Simplify property symbol logic in checkObjectLiteral

This commit is contained in:
Ron Buckton
2017-10-20 23:05:03 -07:00
parent 0b31860c72
commit ccd98af1ba

View File

@@ -5459,7 +5459,7 @@ namespace ts {
if (!(<InterfaceTypeWithDeclaredMembers>type).declaredProperties) {
const symbol = type.symbol;
const members = getMembersOfSymbol(symbol);
(<InterfaceTypeWithDeclaredMembers>type).declaredProperties = getNamedMembers(getMembersOfSymbol(symbol));
(<InterfaceTypeWithDeclaredMembers>type).declaredProperties = getNamedMembers(members);
(<InterfaceTypeWithDeclaredMembers>type).declaredCallSignatures = getSignaturesOfSymbol(members.get(InternalSymbolName.Call));
(<InterfaceTypeWithDeclaredMembers>type).declaredConstructSignatures = getSignaturesOfSymbol(members.get(InternalSymbolName.New));
(<InterfaceTypeWithDeclaredMembers>type).declaredStringIndexInfo = getIndexInfoOfSymbol(symbol, IndexKind.String);
@@ -14222,17 +14222,10 @@ namespace ts {
typeFlags |= type.flags;
let prop: TransientSymbol;
if (hasLateBindableName(memberDecl)) {
const nameType = checkComputedPropertyName(memberDecl.name);
if (nameType && isTypeUsableAsLateBoundName(nameType)) {
prop = createSymbol(SymbolFlags.Property | SymbolFlags.Late | member.flags, getLateBoundNameFromType(nameType));
}
}
if (!prop) {
prop = createSymbol(SymbolFlags.Property | member.flags, literalName || member.escapedName);
}
const nameType = hasLateBindableName(memberDecl) ? checkComputedPropertyName(memberDecl.name) : undefined;
const prop = nameType && isTypeUsableAsLateBoundName(nameType)
? createSymbol(SymbolFlags.Property | SymbolFlags.Late | member.flags, getLateBoundNameFromType(nameType))
: createSymbol(SymbolFlags.Property | member.flags, literalName || member.escapedName);
if (inDestructuringPattern) {
// If object literal is an assignment pattern and if the assignment pattern specifies a default value