Update resolveEntityName to check for non entity name in property access expression

This commit is contained in:
Kanchalai Tanglertsampan
2017-03-16 13:39:17 -07:00
parent 1c90ef5aad
commit 4980fa4d5d

View File

@@ -1493,9 +1493,23 @@ namespace ts {
}
}
else if (name.kind === SyntaxKind.QualifiedName || name.kind === SyntaxKind.PropertyAccessExpression) {
const left = name.kind === SyntaxKind.QualifiedName ? (<QualifiedName>name).left : (<PropertyAccessEntityNameExpression>name).expression;
const right = name.kind === SyntaxKind.QualifiedName ? (<QualifiedName>name).right : (<PropertyAccessExpression>name).name;
let left: EntityNameOrEntityNameExpression;
if (name.kind === SyntaxKind.QualifiedName) {
left = (<QualifiedName>name).left;
}
else if (name.kind === SyntaxKind.PropertyAccessExpression &&
(name.expression.kind === SyntaxKind.ParenthesizedExpression || isEntityNameExpression(name.expression))) {
left = name.expression;
}
else {
// If the expression in property-access expression is not entity-name or parenthsizedExpression (e.g. it is a call expression), it won't be able to successfully resolve the name.
// This is the case when we are trying to do any language service operation in heritage clauses. By return undefined, the getSymbolOfEntityNameOrPropertyAccessExpression
// will attempt to checkPropertyAccessExpression to resolve symbol.
// i.e class C extends foo()./*do language service operation here*/B {}
return undefined;
}
const right = name.kind === SyntaxKind.QualifiedName ? name.right : name.name;
const namespace = resolveEntityName(left, SymbolFlags.Namespace, ignoreErrors, /*dontResolveAlias*/ false, location);
if (!namespace || nodeIsMissing(right)) {
return undefined;
@@ -1512,7 +1526,13 @@ namespace ts {
}
}
else if (name.kind === SyntaxKind.ParenthesizedExpression) {
return getSymbolOfNode(name.expression);
// If the expression in parenthsizedExpression is not an entity-name (e.g. it is a call expression), it won't be able to successfully resolve the name.
// This is the case when we are trying to do any language service operation in heritage clauses. By return undefined, the getSymbolOfEntityNameOrPropertyAccessExpression
// will attempt to checkPropertyAccessExpression to resolve symbol.
// i.e class C extends foo()./*do language service operation here*/B {}
return isEntityNameExpression(name.expression) ?
resolveEntityName(name.expression as EntityNameOrEntityNameExpression, meaning, ignoreErrors, dontResolveAlias, location) :
undefined;
}
else {
Debug.fail("Unknown entity name kind.");
@@ -21091,7 +21111,7 @@ namespace ts {
return entityNameSymbol;
}
}
if (isPartOfExpression(entityName)) {
if (nodeIsMissing(entityName)) {
// Missing entity name.