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Remove equality check for contextual types

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Mateusz Burzyński
2022-07-21 12:36:38 +02:00
parent 95ba58cced
commit 1c8869deed
1 changed files with 1 additions and 1 deletions
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src/compiler/checker.ts
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@@ -28088,7 +28088,7 @@ namespace ts {
// literal handle it instead.
if (contextualTypeHasPattern) {
const rootPatternParent = findAncestor(contextualType.pattern!.parent, n => n.kind === SyntaxKind.VariableDeclaration || n.kind === SyntaxKind.BinaryExpression || n.kind === SyntaxKind.Parameter);
const spreadOrOutsideRootObject = findAncestor(node, n => n === rootPatternParent || (n.kind === SyntaxKind.SpreadAssignment && getContextualType(n.parent as Expression, /*contextFlags*/ undefined)!.pattern === contextualType.pattern))!;
const spreadOrOutsideRootObject = findAncestor(node, n => n === rootPatternParent || (n.kind === SyntaxKind.SpreadAssignment))!;
if (spreadOrOutsideRootObject.kind !== SyntaxKind.SpreadAssignment) {
for (const prop of getPropertiesOfType(contextualType)) {