Call checkExpression eventhough there is no appropriate type from destructuring of array

This commit is contained in:
Kanchalai Tanglertsampan 2016-08-08 11:55:59 -07:00
parent acfdfe0560
commit 42d61b5098

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@ -4447,9 +4447,14 @@ namespace ts {
return property;
}
// Return the symbol for the property with the given name in the given type. Creates synthetic union properties when
// necessary, maps primitive types and type parameters are to their apparent types, and augments with properties from
// Object and Function as appropriate.
/**
* Return the symbol for the property with the given name in the given type. Creates synthetic union properties when
* necessary, maps primitive types and type parameters are to their apparent types, and augments with properties from
* Object and Function as appropriate.
*
* @param type a type to look up property from
* @param name a name of property to look up in a given type
*/
function getPropertyOfType(type: Type, name: string): Symbol {
type = getApparentType(type);
if (type.flags & TypeFlags.ObjectType) {
@ -12856,6 +12861,9 @@ namespace ts {
return checkDestructuringAssignment(element, type, contextualMapper);
}
else {
// We still need to check element expression here because we may need to set appropriate flag on the expression
// such as NodeCheckFlags.LexicalThis on "this"expression.
checkExpression(element);
if (isTupleType(sourceType)) {
error(element, Diagnostics.Tuple_type_0_with_length_1_cannot_be_assigned_to_tuple_with_length_2, typeToString(sourceType), (<TupleType>sourceType).elementTypes.length, elements.length);
}