microsoft/TypeScript
1
0
Fork 0
mirror of https://github.com/microsoft/TypeScript.git synced 2026-05-17 01:49:57 -05:00
Code Issues Packages Projects Releases 212 Wiki Activity

Fixed error when parsing slashes in RegExp literals.

Browse Source 
Basically we weren't recognizing that a slash can occur in a character class, so we were bailing out too early on code like `/[/]/`.

Fixes issue #318.
This commit is contained in:
Daniel Rosenwasser
2014-07-31 00:32:41 -07:00
committed by Daniel Rosenwasser
parent 853288b65f
commit 35803db2e6
14 changed files with 62 additions and 67 deletions
Download Patch File Download Diff File Expand all files Collapse all files

22
src/compiler/scanner.ts
View File

@@ -831,34 +831,46 @@ module ts {
if (token === SyntaxKind.SlashToken || token === SyntaxKind.SlashEqualsToken) {
var p = tokenPos + 1;
var inEscape = false;
var inClass = false;
var inCharacterClass = false;
while (true) {
// If we've hit EOF without closing off the regex,
// simply return the token we originally parsed.
if (p >= len) {
return token;
}
var ch = text.charCodeAt(p);
// Line breaks are not permissible in the middle of a RegExp.
if (isLineBreak(ch)) {
return token;
}
if (inEscape) {
// Parsing an escape character;
// reset the flag and just advance to the next char.
inEscape = false;
}
else if (ch === CharacterCodes.slash) {
else if (ch === CharacterCodes.slash && !inCharacterClass) {
// A slash within a character class is permissible,
// but in general it signals the end of the regexp literal.
break;
}
else if (ch === CharacterCodes.openBracket) {
inClass = true;
inCharacterClass = true;
}
else if (ch === CharacterCodes.backslash) {
inEscape = true;
}
else if (ch === CharacterCodes.closeBracket) {
inClass = false;
inCharacterClass = false;
}
p++;
}
p++;
while (isIdentifierPart(text.charCodeAt(p))) p++;
while (isIdentifierPart(text.charCodeAt(p))) {
p++;
}
pos = p;
tokenValue = text.substring(tokenPos, pos);
token = SyntaxKind.RegularExpressionLiteral;