Add missing relationship allowing a type to be assignable to a conditional when assignable to both branches (#30639)

* Finally add that missing relationship allowing a type to be assignable to both branches of a conditional

* Explicitly write out Ternary.Maybe

* Add slightly modified example from #25413

* fix sick sentence

* Loosen check to skip false branch constraint check to consider `infer` parameters as always satisfied in the extends clause

* Simplify things a bit, only instantiate once

Co-authored-by: Nathan Shively-Sanders <293473+sandersn@users.noreply.github.com>
This commit is contained in:
Wesley Wigham
2021-03-11 11:56:55 -08:00
committed by GitHub
parent b2d1f537f1
commit 2643e65da4
14 changed files with 5727 additions and 0 deletions

View File

@@ -14607,6 +14607,13 @@ namespace ts {
return type[cache] = type;
}
function isConditionalTypeAlwaysTrueDisregardingInferTypes(type: ConditionalType) {
const extendsInferParamMapper = type.root.inferTypeParameters && createTypeMapper(type.root.inferTypeParameters, map(type.root.inferTypeParameters, () => wildcardType));
const checkType = type.checkType;
const extendsType = type.extendsType;
return isTypeAssignableTo(getRestrictiveInstantiation(checkType), getRestrictiveInstantiation(instantiateType(extendsType, extendsInferParamMapper)));
}
function getSimplifiedConditionalType(type: ConditionalType, writing: boolean) {
const checkType = type.checkType;
const extendsType = type.extendsType;
@@ -18139,6 +18146,36 @@ namespace ts {
}
}
}
else if (target.flags & TypeFlags.Conditional) {
const c = target as ConditionalType;
// Check if the conditional is always true or always false but still deferred for distribution purposes
const skipTrue = !isTypeAssignableTo(getPermissiveInstantiation(c.checkType), getPermissiveInstantiation(c.extendsType));
const skipFalse = !skipTrue && isConditionalTypeAlwaysTrueDisregardingInferTypes(c);
// Instantiate with a replacement mapper if the conditional is distributive, replacing the check type with a clone of itself,
// this way {x: string | number, y: string | number} -> (T extends T ? { x: T, y: T } : never) appropriately _fails_ when
// T = string | number (since that will end up distributing and producing `{x: string, y: string} | {x: number, y: number}`,
// to which `{x: string | number, y: string | number}` isn't assignable)
let distributionMapper: TypeMapper | undefined;
const checkVar = getActualTypeVariable(c.root.checkType);
if (c.root.isDistributive && checkVar.flags & TypeFlags.TypeParameter) {
const newParam = cloneTypeParameter(checkVar);
distributionMapper = prependTypeMapping(checkVar, newParam, c.mapper);
newParam.mapper = distributionMapper;
}
// TODO: Find a nice way to include potential conditional type breakdowns in error output, if they seem good (they usually don't)
let localResult: Ternary | undefined;
if (skipTrue || (localResult = isRelatedTo(source, distributionMapper ? instantiateType(getTypeFromTypeNode(c.root.node.trueType), distributionMapper) : getTrueTypeFromConditionalType(c), /*reportErrors*/ false))) {
if (!skipFalse) {
localResult = (localResult || Ternary.Maybe) & isRelatedTo(source, distributionMapper ? instantiateType(getTypeFromTypeNode(c.root.node.falseType), distributionMapper) : getFalseTypeFromConditionalType(c), /*reportErrors*/ false);
}
}
if (localResult) {
resetErrorInfo(saveErrorInfo);
return localResult;
}
}
else if (target.flags & TypeFlags.TemplateLiteral && source.flags & TypeFlags.StringLiteral) {
if (isPatternLiteralType(target)) {
// match all non-`string` segments