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Make string literals valid constituent types nodes in the parser.

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Daniel Rosenwasser
2015-10-01 15:55:36 -07:00
parent f04cc39a68
commit 191be4f8fe
1 changed files with 3 additions and 3 deletions
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6
src/compiler/parser.ts
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@@ -1969,9 +1969,7 @@ namespace ts {
function parseParameterType(): TypeNode {
if (parseOptional(SyntaxKind.ColonToken)) {
return token === SyntaxKind.StringLiteral
? <StringLiteral>parseLiteralNode(/*internName*/ true)
: parseType();
return parseType();
}
return undefined;
@@ -2359,6 +2357,8 @@ namespace ts {
// If these are followed by a dot, then parse these out as a dotted type reference instead.
let node = tryParse(parseKeywordAndNoDot);
return node || parseTypeReferenceOrTypePredicate();
case SyntaxKind.StringLiteral:
return <StringLiteral>parseLiteralNode(/*internName*/ true)
case SyntaxKind.VoidKeyword:
return parseTokenNode<TypeNode>();
case SyntaxKind.TypeOfKeyword: